Sujet : Re: There is a first/smallest integer (in Mückenland)
De : richard (at) *nospam* damon-family.org (Richard Damon)
Groupes : sci.mathDate : 20. Jul 2024, 14:30:53
Autres entêtes
Organisation : i2pn2 (i2pn.org)
Message-ID : <7d8fa2b5ebe392d5784452f4e1d12b2da7254504@i2pn2.org>
References : 1 2 3 4 5 6 7 8 9 10 11
User-Agent : Mozilla Thunderbird
On 7/20/24 8:47 AM, WM wrote:
Le 19/07/2024 à 20:52, Jim Burns a écrit :
On 7/19/2024 9:53 AM, WM wrote:
Then we can abbreviate each and every x > 0 by (0, oo).
>
Your "abbreviating" is a quantifier shift.
Making it less visible doesn't make it prove anything.
My theorem: X is left-hand side of every x > 0 <==> X is left-hand side of (0, oo).
Find a counter example or accept it.
If you believe it can be interpreted as a quantifier shift, then note that not every quantifier shift produces a wrong result. Example: see above.
>
"Abbreviate" rock.paper.scissors and
you get wrong answers.
That method is unreliable.
Don't waffle, do what is usual in mathematics: Show a counter example for my theorem.
Regards, WM
But no value of x can BE that left hand side of (0, oo) because if such an x did exist then x/2 would be outside the interval, but also positive.
The fact being that these systems are UNBOUNDED, and thus there does not exist a number "next to" another number, but we just have an infinite density of numbers.