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On 02.02.2025 01:33, Richard Damon wrote:But N is in the union of any inifinite set of FISONs.On 2/1/25 1:17 PM, WM wrote:I think you've got it! Yes, U(A(n)) is not ℕ.The set of FISONs assumed to satisfy U(A(n)) = ℕ cannot be empty. But we can prove by induction that every FISON can be discarded without changing the union. That disproves the assumption.And that is your problem, you make assumptions that are unwarented,
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Regards, WM
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