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On 10.10.2024 20:45, Alan Mackenzie wrote:You might think so, but that ignores the laws of mathematics of infinite values.WM <wolfgang.mueckenheim@tha.de> wrote:There are no infinite n = natural numbers.If all natnumbers are there and if 2n is greater than n, then the>
doubled numbers do not fit into ℕ.
For any finite n greater than zero, 2n is greater than n. The same
does not hold for infinite n.
Deplorable. But note that all natural numbers are finite and follow this law: When doubled then 2n > n. If a set of natural numbers is doubled, then the results cover a larger set than before.>Numbers multiplied by 2 do not remain unchanged. That is not intuition
but mathematics.>True,Fine, then you can follow the above discussion. Either doubling creates>
new natural numbers. Then not all have been doubled. Or all have been
doubled, then some products fall outside of ℕ.
No. Not even close.
Regards, WM
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