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On 02.01.2025 19:19, Jim Burns wrote:It is very obvious there are infinitely many FISONs.On 1/2/2025 6:31 AM, WM wrote:That is impossible, because all finite ordinals can be subtracted from ℕOn 31.12.2024 21:26, Jim Burns wrote:On 12/31/2024 1:20 PM, WM wrote:So it is for each finite.ordinal.So it is for all definable natural numbers.Every union of FISONs which stay below a certain threshold staysFor each finite ⟦0,j⦆, there are more.than.#⟦0,j⦆.many finite ⟦0,k⦆
below that threshold.
Note: Every FISON stays below 1 % of ℕ.
without infinitely many remaining. If you don't understand that, it is
useless to go on.
>Infinitely many can be removed without remainder. But only finitely manynatural numbers which have only few successors because when they are... the non.finite.ordinal natural.numbers.
removed nothing remains ℕ \ {1, 2, 3, ...} = { } .
We define natural.numbers to be only finite.ordinals, of which there
are more.than.any.finite.many.
can be defined by FISONs.
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