Re: Incompleteness of Cantor's enumeration of the rational numbers (extra-ordinary)

Le 08/12/2024 à 23:34, Crank Wolfgang Mückenheim from Hochschule Augsburg aka WM a écrit :

On 08.12.2024 19:01, Jim Burns wrote:

On 12/8/2024 5:50 AM, WM wrote:

 

∀n ∈ ℕ: E(1)∩E(2)∩...∩E(n) = E(n)
What can't you understand here?

 {E(i):i} is the set.of.all non.empty end.segments.
 ⋂{E(i):i} is the intersection.of.all

non.empty end.segments.

 ∀n ∈ ℕ:
{E(i):i}∪{E(n+1)} = {E(i):i}
Each is "already" in.

 Not the empty endsegment.
∀n ∈ ℕ: E(n) is non-empty. But not every E(n+1).

You could hardly write something worse and more wrong that that.
The very core property of N is that if n ∈ ℕ then n+1 ∈ ℕ.
Are you again "teaching" your nonsense and abusing students at Hochschule Augsburg, (not) dear (bun infamous) Crank Wolfgang Mückenheim?