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On 23.11.2024 22:48, Jim Burns wrote:No. "Almost all" means everything except for a finite number.On 11/23/2024 3:45 PM, WM wrote:But almost all numbers are without hat because the number of hats hasThank you.⎜ Assume that there are ⎜ enough red hats for the first 𝔊 numbers ⎜That is a mistake.
but not enough for the 𝔊+1ᵗʰ
If there are enough hats for G natnumbers,
then there are also enough for G^G^G natnumbers.
Alas they leave G^G^G unit intervals without hats.After all hat.shifts,
That is the catch!
there is no first number without a hat.
not increased.
It is still valid for every finite interval.After all hat.shifts,Then the number of hats must have increased.
the set of numbers without hats is empty.
Then number theory can be wasted, because its formula for n/logn primes
in (0, n] is no longer valid after Cantor-reordering.
Bob is in none of them.He is in a dark room.After all swaps, Bob is not in any room (visible or dark)Shall unit intervals disappear like Bob?There are too few prime numbers.No, there being too few primes leads to contradiction.
which Bob has ever been in.But the unit intervals remain steadfast on the real line.
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