Sujet : Re: Does the number of nines increase?
De : noreply (at) *nospam* example.org (joes)
Groupes : sci.mathDate : 04. Jul 2024, 12:00:09
Autres entêtes
Organisation : i2pn2 (i2pn.org)
Message-ID : <b5b447c6d11dfdb91d814fc51296a21b660a0bce@i2pn2.org>
References : 1 2 3 4 5 6 7 8 9 10 11
User-Agent : Pan/0.145 (Duplicitous mercenary valetism; d7e168a git.gnome.org/pan2)
Am Wed, 03 Jul 2024 20:05:48 +0000 schrieb WM:
Le 03/07/2024 à 19:09, Moebius a écrit :
Am 28.06.2024 um 15:55 schrieb WM:
in {0, 1, 2, 3, ..., ω} before ω there is a natural number.
Ja, "before ω" (im Sinne von kleiner) sind unendlich viele natural
numbers, nämlich die natürlichen Zahlen 0, 1, 2, 3, ... usw.
Es gibt aber keine natürliche Zahl die "unmittelbar vor" ω steht.
You cannot recognize it. It is existing but dark.
Zu jeder natürlichen Zahl n gibt es eine natürliche Zahl m
(beispielsweise n+1),
so dass n < m < ω gilt.
For every visible natural number this is true.
There is no such thing as „visibility”.
Like ∀x > 0: NUF(x) = ℵo is true. But this truth proves the existence of
dark numbers, because between every such x and 0 there must lie ℵo unit
fractions and ℵo finite distances between them.
Why? That distance can be divided infinitely.
-- Am Fri, 28 Jun 2024 16:52:17 -0500 schrieb olcott:Objectively I am a genius.