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On 8/30/24 8:59 AM, WM wrote:Le 30/08/2024 à 12:13, Moebius a écrit :Am 30.08.2024 um 09:21 schrieb joes:
Not both can be the smallest. Hence only one is the first.No, because nothing is smaller than itself, and two unequal order things must have an order.So no matter if x > 0 is infinitesimal or not: NUF(x) =/= 1.Are there two unit fractions possible lessorequal than all unit fractions?
But there ARE two unit fractions less than ANY given unit fraction.Of course. Any given unit fraction can be given and therefore is visible.
You just apply the wrong qualifiers because you logic system is broken.No. I apply this way in oder to show the more intelligent readers among you, than there is NUF(x) = 1.
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