Re: how

Le 29/05/2024 à 20:29, Jim Burns a écrit :

On 5/29/2024 1:11 PM, WM wrote:

Le 28/05/2024 à 21:42, Jim Burns a écrit :

On 5/27/2024 4:10 PM, WM wrote:

 

If a set of real numbers has no elements below 0,
then it ends

>
Support your claim.

>
The set has ended where no elements follow.

 Consider a set B of real numbers such that
real number x exists such that
x ≤ each element of B
 Are you (WM) claiming that
⎛ B.element b′ exists such that
⎝ b′ ≤ each element of B
?

The answer is no/yes. b is impossible to find. b exists.

 If, yes, that is your claim,
then please support that claim.

I did so already using unit fractions. NUF(x) = 1 between x = 0 and x = 1/10^10^10^100000.
This is proven by the mathematics of unit fractions
∀n ∈ ℕ: 1/n - 1/(n+1) = 1/(n(n+1)) > 0 .
Never two appear simultaneously.

The set is not where no elements are.
If the set was before,
then it has ended meanwhile.

 Are you claiming that
the set holds an element ≤ each element?
 If, yes, you claim that,
then please support that claim.

Bob!

 

isn't logic.
Finite sequences of not.first.false claims
are logic.

Your sequences of not.first.false claims leads to the result that elements can disappear by exchange. You should recognize that this is impossible. Therefore, if your chain contains only correct conclusions, then your start must be wrong.
Regards, WM