Sujet : Re: Does the number of nines increase?
De : james.g.burns (at) *nospam* att.net (Jim Burns)
Groupes : sci.mathDate : 01. Jul 2024, 05:22:22
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <d0731868-9467-4a96-9c0a-105f5e30ab57@att.net>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17
User-Agent : Mozilla Thunderbird
On 6/30/2024 11:32 PM, Ross Finlayson wrote:
On 06/30/2024 06:38 PM, Jim Burns wrote:
On 6/30/2024 5:05 PM, Ross Finlayson wrote:
Well, iota-values are defined and
satisfy making for the IVT
which results the FTC's,
Fundamental Theorems of Calculus.
>
If I use the usual definitions for
the limit of a sequence of sets
for your iota.values,
they do not satisfy the Intermediate Value Theorem.
>
I understand your iota.values to be the limit
n/d: 0≤n≤d: d → ∞
>
For n/d: 0≤n≤d I read {0/d,1/d,...,d/d}
>
For lim[d → ∞] I read ⋂[0<dᵢ<∞] ⋃[dᵢ<d<∞]
>
Is that what you mean? You (RF) don't say.
>
⋂[0<dᵢ<∞] ⋃[dᵢ<d<∞] {0/d,1/d,...,d/d}
does not satisfy the Intermediate Value Theorem.
Yes it does, the iota-values result that they do
make for the IVT,
Tell me what you are talking about.
I understand your iota.values to be the limit
n/d: 0≤n≤d: d → ∞
For n/d: 0≤n≤d I read {0/d,1/d,...,d/d}
For lim[d → ∞] I read ⋂[0<dᵢ<∞] ⋃[dᵢ<d<∞]
Is that what you mean? You (RF) don't say.
⋂[0<dᵢ<∞] ⋃[dᵢ<d<∞] {0/d,1/d,...,d/d}
does not satisfy the Intermediate Value Theorem.