Sujet : Re: How many different unit fractions are lessorequal than all unit fractions? (infinitary)
De : james.g.burns (at) *nospam* att.net (Jim Burns)
Groupes : sci.mathDate : 23. Oct 2024, 19:39:04
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <d316baa3-de5b-4644-86ff-beacad9df107@att.net>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
User-Agent : Mozilla Thunderbird
On 10/22/2024 2:34 PM, WM wrote:
On 22.10.2024 19:38, Jim Burns wrote:
The description of each element in ℕ
requires its double to also be in ℕ
>
All that is in ℕ, according to your opinion,
is accepted.
In the ℕ which is our ℕ,
n ∈ ℕ ⇔ ∃⟨0,1,...,n-1,n⟩
In the ℕ which is our ℕ,
for each j ∈ ℕ, ∃k ∈ ℕ: k = j+1
for each j ∈ ℕ, j=0 ∨ ∃i ∈ ℕ: i+1=j
for each S s ℕ, S = {} ∨ ∃m ∈ S: m=min.S
Bob is in room 0 of our ℕ.Hotel
Swap guests in 0⇄1, 1⇄2, 2⇄3, 3⇄4, ...
After all swaps,
there is no first room Bob is in.
There is no ▒▒▒▒▒ room Bob is in.
'Bye, Bob.
If you find that the set ic complete,
then it is doubled.
In a WM.complete ℕ.Hotel,
dark rooms are added for Bob to disappear to
when he isn't in the visible rooms,
repairing 'bye.Bob,
leaving can't.see.Bob.
However,
none of these swaps 0⇄1, 1⇄2, 2⇄3, 3⇄4, ...
move Bob to a dark room.
Bob disappeared
without going to a dark room.
Adding dark rooms without Bob in them
does not repair 'bye.Bob.
There is no
'bye.Bob.repairing WM.complete Hotel.
...not so different from the way in which
the description of a right triangle
requires
the square of its longest side to equal
the sum of the squares of the two other sides.
>
Your above expression is in fact
a very closely related one.
The most mathematical action one can perform is
to accept a result one sees is correct but
does not want to be correct.