Sujet : Re: 2N=E
De : noreply (at) *nospam* example.org (joes)
Groupes : sci.mathDate : 03. Nov 2024, 16:55:56
Autres entêtes
Organisation : i2pn2 (i2pn.org)
Message-ID : <d76e020d7e690a7a993014bc977b979186b70da6@i2pn2.org>
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User-Agent : Pan/0.145 (Duplicitous mercenary valetism; d7e168a git.gnome.org/pan2)
Am Sun, 03 Nov 2024 12:56:48 +0100 schrieb WM:
On 03.11.2024 09:50, joes wrote:
pparently you do think that there is a natural n such that 2^n is
infinite.
If all naturals are there, then no further one is available. But
doubling all yields a greater number than all.
In actual infinity there is no way to avoid this.
We don't need any further ones because we ALREADY HAVE ALL OF THEM,
even including the doubles.
-- Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:It is not guaranteed that n+1 exists for every n.