Re: The set of necessary FISONs

On 1/26/25 3:41 AM, WM wrote:

On 25.01.2025 14:56, joes wrote:
 

There is obviously no single FISON that is equal to N.

 Obviously every union of FISONs is finite, because there are never two consecutive actually infinite sets in ℕ, and every FISON has an infinite set as successors.
 Obviously every unbion of FISONs is a FISON.

Every union of a FINITE number of FISONs is finite.
The problem is that you then apply that to a union of an INFINITE set of FISON.

>

Do you agree that or every FISON the question whether it is necessary
can be answered?

Yes, in the negative. That does not imply the nonexistence of a
sufficient set.

 It implies that there is not a first FISON. That proves by induction that every FISON can be dropped. Your belief is dysfunctional logic.

No, it implies that the "set of necessary FISONs" doesn't exist.
Only by having the FALSE premise of the existance of such a set, can you do your induction,
Of course, by that same logic, 1 is equal to 2, and nothing, and everything is true and false.

 Regards, WM