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On 4/6/24 9:26 AM, WM wrote:That mapping is Cantor's proposal. But for every other mapping, the O's would also remain. All O's! It is th lossless exchange which proves it.Le 05/04/2024 à 12:57, FromTheRafters a écrit :No, not "No Bijection", but that mapping isn't a bijection.WM explained on 4/4/2024 :Of course. But if someone doubts it, I could directly map the naturals n/1 to the fractions with the result that there is no bijection.Explain why first bijecting n and n/1 should destroy an existing bijection!>
You still seem to think that sets change. If you mean 'n' is an element of the naturals then of course N bijects with the naturals as embedded in Q.
It is Cantor's famaous mapping, more than a century believed to be a bijection.No, that is disproved by the remaining Os.Which only shows that this one mapping doesn't work.
And, when you try it within one set, as opposed to between two sets,If it operates, it must operate within one set too.
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