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Le 12/04/2024 à 20:57, Jim Burns a écrit :ALL elements of ℕ are individually usable, there is not finite number n that is the highest usable number, which is the fundamental FLAW in your logic, which makes it just BLOW UP.On 4/12/2024 9:18 AM, WM wrote:usedᵂᴹ or not.usedᵂᴹAll individually usable numbers satisfy
not.exists
∀n ∈ ℕ_ind: |ℕ \ {1, 2, 3, ..., n}| = ℵo.
All collectively useable numbers satisfy
|ℕ \ {1, 2, 3, ...}| = 0
NONE.What elements of {1, 2, 3, ..., ω}*2 fall between ω and ω*2?What elements fall between ω and ω*2?>
ω+1 ω+2 ...
Their distances must be 2.
None.>No, the question is: What elements of {1, 2, 3, ..., ω}*2 fall between ω and ω*2?What size has the interval between ℕ*2 and ω*2?>
I take you to be asking how many ordinals are
after each of {2,4,6,...} and before ω+ω
Nope, because the "gap" doesn't have a defined distance, just an ordering.>Then {1, 2, 3, ..., ω}*2 increases the gap between {1, 2, 3, ...} and ω from 0 to infinity. Very bumpy. Only a factor 2 is possible when doubling.
No doubled ordinal is between ω and ω+ω
Regards, WM
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