Re: how

On 4/26/24 10:41 AM, WM wrote:

Le 26/04/2024 à 04:03, Richard Damon a écrit :
 

If ω is existing, then something is next.

>
next above, yes, ω+1
>
next below, no,

 I disagree.

Which makes you wrong.

 

the problem is the set below it is unbounded,

 The set is bounded by ω.

But ω isn't in the set, so it can't be the upper bound of the set that is below ω
Your logic just said that ω is the number before ω, so got stuck in a infinite loop.
After all, if the number below ω is the upper bound of the set of Natural Numbers, and that is itself ω, then the number below ω must be ω by your logic.
BOOM.

 

and thus doesn't have a "highest" value in it.

 The value is there but invisible.
 

Nope. No such thing.

Regards, WM