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Le 26/08/2024 à 02:15, Moebius a écrit :Define visible? lol. ;^) Give me any natural number x. 1/x. Okay, what about (1/(x+1))? There is no smallest unit fraction just like there is no largest natural number... See?Am 25.08.2024 um 23:18 schrieb Jim Burns:Dark natural numbers are larger than any visible natural number but smaller than their bound omega.On 8/25/2024 3:35 PM, WM wrote:>>Dark numbers are not any bounds.
Fascinating: So we have that there are "dark numbers" which are smaller (larger) than each and every s e SB (n e IN), but they are no bounds?
Dark unit fractions are smaller than any visible unit fractions but larger than their bound 0.
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