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On 07.09.2024 16:05, Python wrote:x = 1/k - 1/(k+1) = 1/[k*(k+1)] > 0Le 07/09/2024 à 15:03, WM a écrit :Select any gap between one of the first ℵo unit fractions and its neighbour. Call its size x.Stop that nonsense. ℵo unit fractions cannot fit into every interval (0, x).>
Of course they can.
Then ℵo unit fractions cannot fit into the interval (0, x), independent of the actual size.It can and it does : { 1/p : p > k*(k+1) } has cardinal ℵo,
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