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On 10/24/2024 2:58 PM, WM wrote:
The whole interval (0, ω) is not finite, let alone the doubled interval.The whole set with all its numbers existsYes.
and can be mapped to the double numbers.
∃⟨0,1,...,n-1,n⟩ ⇒
∃⟨0,1,...,n-1,n,n+1,...,n+n-1,n+n⟩
That halves the densityNo.
and doubles the covered interval.
⟨0,1,...,n-1,n,n+1,...,n+n-1,n+n⟩ is finite.
Bob of the matricesThat Bob is not in any room he was ever inAfter all swaps,>
Bob is not in any room he was ever in.
'Bye, Bob.
After all swaps Bob is in a room,
because there is nowhere an outlet.
and there is nowhere an outlet
proves the set is infinite.
If the infinite set has been used completely for counting then Bob stays in a dark cell.Bobs cannot dissolve into nothing.Bob can be in an infinite set.
If all natnumbers can be issued, Bob is in a dark cell because further nothing happens.After all swaps,The problem with Bob disappearing is that>
Bob disappearing is not a problem.
It's not repairable because it's not broken.
Lossless exchanges remain lossless forever.
Bob is not in any room he was ever in.
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