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On 10/25/2024 7:42 AM, WM wrote:
Correct so far.The whole interval (0, ω) is not finite,⟦0,ω⦆ is the set of finite ordinals.
let alone the doubled interval.
That is the definition of finite ordinal.
That is the definition of ω,
the first ordinal after all finite ordinals.
γ before ω: γ is finite.That is wrong in complete infinity.
γ ∈ ⟦0,ω⦆ ⇒
∀β ∈ ⦅0,γ⟧: ∃α: α+1=β
ω before ξ: ξ is not finite.
ω ∈ ⦅0,ξ⟧ ⇒
¬∀β ∈ ⦅0,ξ⟧: ∃α: α+1=β
(Keep in mind that ¬∃α: α+1=ω )
A better question is:I support it in order to show that your infinity is inconsistent.
why do you (WM) support it?
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