Sujet : Re: 2N=E
De : wolfgang.mueckenheim (at) *nospam* tha.de (WM)
Groupes : sci.mathDate : 25. Oct 2024, 17:59:53
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <vfgiqa$38oob$1@dont-email.me>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
User-Agent : Mozilla Thunderbird
On 25.10.2024 18:54, Jim Burns wrote:
On 10/24/2024 10:29 AM, WM wrote:
The set, when existing completely,
covers an interval, namely (0, ω).
When its density is halved
while the number of elements is constant,
then its extension is doubled.
No.
⟨0,1,...,n-1,n,n+1,...,n+n-1,n+n⟩ is finite.
The extension is doubled in this finite set here as well as in my infinite set.
Regards, WM
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