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On 29.10.2024 01:21, Richard Damon wrote:That's the point (pun unintended).On 10/28/24 3:52 PM, WM wrote:There are no others on the real line.On 28.10.2024 12:21, Richard Damon wrote:Of course it can. just not at any finite value.On 10/28/24 6:36 AM, WM wrote:>It has the value 0 for all x =< 0. And it cannot jump by more than 1NUF increases by 1 or more, but more would violate mathematics.No, NUF(x) jumps from 0 to Aleph_0 in the domain of finite numbers,
because there is no finite x where it has the value of 0.
at any point.
I.e. infinitesimal.The nit is dark.No, but the first steps happen at undefinable x.No, it happens at an x that isn't a finite number.
Then there is no x with NUF(x)=1.If you allow your NUF to accept infintesimal numbersNo, that is strongly forbidden.
The infimum is 0.Then it is dark bottom.No, the bottom is outside the set.That is true. The bottom is dark.This infinity between 0 and (0, 1] is not what I can accept.Note, it isn't an "infinity between" it is that the "bottom" of (0,
1] doesn't exist as a definable point.Your "Darkness" is just your attempt to hide the problems with yourAnd your bottom outside the set is what?
logic.
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