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On 10/30/2024 3:55 PM, WM wrote:But the first formula predicts that only single unit fractions are existing on the real line. How could NUF(x) grow from zero by more than 1?On 30.10.2024 18:05, Jim Burns wrote:Neither∀ᴿx > 0: ∀n ∈ ℕ: ⅟⌈n+⅟x⌉ ∈ ⅟ℕ∩(0,x]>
>
∀ᴿx > 0: NUF(x) = |ℕ|
Is ∀n ∈ ℕ: 1/n - 1/(n+1) > 0 wrong?
∀n ∈ ℕ: 1/n - 1/(n+1) > 0
nor
∀ᴿx > 0: ∀n ∈ ℕ: ⅟⌈n+⅟x⌉ ∈ ⅟ℕ∩(0,x]
is wrong.
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