Sujet : Re: 2N=E
De : wolfgang.mueckenheim (at) *nospam* tha.de (WM)
Groupes : sci.mathDate : 03. Nov 2024, 12:56:48
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <vg7oe0$9ma8$7@dont-email.me>
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User-Agent : Mozilla Thunderbird
On 03.11.2024 09:50, joes wrote:
pparently you do think that there is a
natural n such that 2^n is infinite.
If all naturals are there, then no further one is available. But doubling all yields a greater number than all.
In actual infinity there is no way to avoid this.
Regards, WM