Sujet : Re: 2N=E
De : invalid (at) *nospam* example.invalid (Moebius)
Groupes : sci.mathDate : 04. Nov 2024, 17:58:39
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <vgaug0$11cg8$3@dont-email.me>
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User-Agent : Mozilla Thunderbird
Am 04.11.2024 um 17:50 schrieb Moebius:
Am 04.11.2024 um 12:33 schrieb Chris M. Thomasson:
Infinite ways to represent 1:
>
1 = 4 - 2 - 1
1 = 3*2 - 5
1 = 1 + 1 - 1
1 = ...
>
?
Right. {4 - 2 - 1, 3*2 - 5, 2 - 1, 3 - 2, 4 - 3, ...} = {1} (though FromTheAfter is too dumb to get that).
This idiot is convinced that "in any case" |{x, y, z}| = 3.
Actually,
|{x, y, z}| = 3 iff x =/= y and x =/= z and y =/= z.
In case of, say, x = y = z = 1 we have |{x, y, z}| = |{1}| = 1.
All idiots are equal, but some are more equal than others.