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Am Tue, 17 Dec 2024 10:13:48 +0100 schrieb WM:
It is also the set because every FISON can represent one natnumber.Every element is the last element of a FISON [1, n]. ℕ is the set of allNo, it is the union.
FISONs.
It is all FISONs.I use all FISONs.No, you don’t. N is not a FISON.
You claimed that he uses more than I do, namely all natural numbers.What else do you think it uses?According to Cantor the "bijection" uses all n and nothing more.All intervals do it because there is no n outside of all intervals [1,And all the intervals are finite, and thus not the INFINITE set N,
n]. My proof applies all intervals.
which is where the bijection occurs.
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