Re: New way of dealing with complex numbers

Am 08.03.2025 um 14:32 schrieb efji:

Le 08/03/2025 à 14:18, Richard Hachel a écrit :

Associativity is MANDATORY to be able to write something like i^4 = i*i*i*i.
>
For a non associative operator, i^4 means NOTHING.

Oh, i^(n+1) just might mean (i^n) * i (with n e IN).
[And i^0 = 1.]
Then: i^4 = ((i*i)*i)*i.
[Hint: recursive definition:
  x^0 = 1
  x^(n+1) = x^n * x   (for all n e IN)]