Re: The splendor of true

Le 10/03/2025 à 03:03, Chris M. Thomasson a écrit :

 Indeed. Sorry for the stupid question, but the following parts of RH's description:
 Z=aa'+bb'+i(ab'+a'b) and not Z=aa'-bb'+i(ab'+a'b).
 Means a = x component, b = y component, right? ;^o

Well...
In his disturbed mind, (a,b) = a-b on the x axis :)
But forget the pathetic egotic and just try a+jb=(a,b) un R^2 with the rule (a+ib)*(a'+jb') = aa'+bb'+j(ab'+a'b) which is the rule on the split-complex set, (thus j^2=1).
--
F.J.