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Am Sun, 09 Mar 2025 20:13:53 +0100 schrieb WM:
That is no my opinion but Jim Burns' opinion.I am interested in the difference that you see betweenHow you can view the first set not to have the same union (by Neumann's
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Z₀ defined by { } ∈ Z₀, and if {{{...{{{ }}}...}}} with n curly brackets
∈ Z₀ then {{{...{{{ }}}...}}} with n+1 curly brackets ∈ Z₀
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and
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The set of FISONs failing to have the union ℕ defied by induction:
|ℕ \ {1}| = ℵo, and if |ℕ \ {1, 2, 3, ..., n}| = ℵo then |ℕ \ {1, 2, 3,
..., n+1}| = ℵo.
equivalence) as the the second one would be most welcome.
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