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WM schrieb:Right! But ω remains like 6 remains.
Le 13/04/2024 à 21:16, Jim Burns a écrit :The smallest ordinals behind all n in IN possible would be the w's in something like {0, 1, 2, 3, ..., w, w+1, w+2, w+3, ... w+w}On 4/13/2024 8:35 AM, WM wrote:Doubling of ordinalsWhat elements of {1, 2, 3, ..., ω}*2Why 2 ?
fall between ω and ω*2?
Their distances must be 2.
which, under f(n)=n*2, has the image
{0, 2, 4, 6, ..., w*2, w*2+2, w*2+4, w*2+4, ... w*2+w*2}
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