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Le 30/03/2024 à 19:47, Richard Damon a écrit :No true. That would be akin to saying every map is conformal. Totally wrong.On 3/30/24 12:01 PM, WM wrote:It is true for every mapping.Le 29/03/2024 à 14:29, Richard Damon a écrit :>
>And, it can be shown that ℕ and ℚ are the same size.>
That is believed by some stupids who are too dense to understand logic. The Os in the matrix
XOOO...
XOOO...
XOOO...
XOOO...
..
cannot disappear by exchange with Xs.
So?
>
That isn't the Bijection we are looking for.
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