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Le 31/03/2024 à 20:18, Richard Damon a écrit :So, that's not the way to show it.On 3/31/24 8:15 AM, WM wrote:>>Nope, only if you try to biject WITH a set, and not between two DIFFERENT sets.It is true for every mapping.>And, it can be shown that ℕ and ℚ are the same size.>
That is believed by some stupids who are too dense to understand logic. The Os in the matrix
XOOO...
XOOO...
XOOO...
XOOO...
..
cannot disappear by exchange with Xs.
So?
>
That isn't the Bijection we are looking for.
The different sets are ℕ and ℚ. The bijection with the first column does not change that.
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