Re: how

On 4/9/2024 4:00 PM, Chris M. Thomasson wrote:

On 4/9/2024 5:16 AM, WM wrote:

Le 09/04/2024 à 01:22, Richard Damon a écrit :

On 4/8/24 9:44 AM, WM wrote:

Le 07/04/2024 à 19:56, Richard Damon a écrit :

On 4/7/24 9:23 AM, WM wrote:

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So, With infinite sets, a proper subset CAN be the same size as its parent.

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Impossible.

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Nope, PROVEN.

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Proven impossble with my matrix,

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Nope, since you matrix doesn't follow the required form.

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It does precilsely.
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and we can build such a mapping between the set of natural Numbers (N) with the set of even Numbers (E).

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Only handwaving by "and so on"

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In all cases there are infinitely many exceptions.
∀n ∈ ℕ_applied: |ℕ \ {1, 2, 3, ..., n}| = ℵo.

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I didn't say "N_applied", I said N.

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But what you can use belongs to ℕ_applied. Otherwise show a natural number that completes the bijection, i.e., which has not infinitely many pairings on front.

 Are you some sort hardcore abortion survivor? What happened to you?
 

Did you manage to survive the process? Well, if so, there has been a lot of damage. Damn it WM, there is no largest natural number... Sorry for being an asshole here, but god damn.