Re: how

Le 17/04/2024 à 21:38, Tom Bola a écrit :

WM drivels bullshit again and again, as always:
 

Le 16/04/2024 à 21:48, Tom Bola a écrit :

WM schrieb:

 

Nevertheless the question remains where in the second row is ω located, doesn't it?.

 NOPE - because w is not in the IMAGE of your f(ord) = 2*ord 

ω*2 is present. Therefore ω or the ordinals next to it must be localized below.

 Also, 2, 4, 6, ... are present in the image but not 1, 2, 3, ...

If you accept set theory, then you have to accept too that there is no ordinal between ℕ and ω. The interval populated by ℕ  is (0, ω). By doubling the number of elements remains the same, but the populated interval is (0, ω2) with ω amidst.
I do not claim that ω is in the image, but it is amidst the interval. That proves that doubled numbers surpassed it.
Regards, WM