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On 4/17/24 4:30 PM, WM wrote:
I do not claim that ω is in the image, but it is amidst the interval. That proves that doubled numbers surpassed it.
Only the ω doubled passed it. The rest stayed below ω, and no natural number doubled isn't a natural number.You are wrong. ω is amidst the interval (0, ω2) because in the image there are as many ordinals in (ω, ω2) as in (0, ω).
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