Liste des Groupes | Revenir à s math |
Le 18/04/2024 à 01:26, Richard Damon a écrit :But all those ordinals are transfinite ordinals, and none are the value of double a finite Natural Number.On 4/17/24 4:30 PM, WM wrote:I do not claim that ω is in the image, but it is amidst the interval. That proves that doubled numbers surpassed it.Only the ω doubled passed it. The rest stayed below ω, and no natural number doubled isn't a natural number.You are wrong. ω is amidst the interval (0, ω2) because in the image there are as many ordinals in (ω, ω2) as in (0, ω).
Regards, WM
Les messages affichés proviennent d'usenet.