Re: how

Chris M. Thomasson schrieb:

On 4/19/2024 8:20 AM, WM wrote:

Le 19/04/2024 à 00:35, Richard Damon a écrit :

On 4/18/24 11:05 AM, WM wrote:

ω is amidst the interval (0, ω2) because in the image there are as
many ordinals in (ω, ω2) as in (0, ω).

>
But all those ordinals are transfinite ordinals, and none are the
value of double a finite Natural Number.

 
You are in error. Counting goes like this: 1, 2, 3, ..., ω, ω+1, ω+2, ..
You simply pass ω although no known natural number k+1 will reach ω. But
by multiplication, which goes faster, you cannot pass ω?

 
Huh?
 
any_natural_number * 2 = another_natural_number
 
These natural numbers are already in the set of all natural numbers.

WM knows that definition but he doesn't ACCEPT it in his own math
since 30++ years (which he doesn't mention this difference) because
he feels that the used logic in today's mathematics is very wrong.