Re: how

Le 19/04/2024 à 00:35, Richard Damon a écrit :

On 4/18/24 11:05 AM, WM wrote:

ω is amidst the interval (0, ω2) because in the image there are as many ordinals in (ω, ω2) as in (0, ω).

 But all those ordinals are transfinite ordinals, and none are the value of double a finite Natural Number.

>
You are in error. Counting goes like this: 1, 2, 3, ..., ω, ω+1, ω+2, .. You simply pass ω although no known natural number k+1 will reach ω. But by multiplication, which goes faster, you cannot pass ω?