Sujet : Re: how
De : moebius (at) *nospam* example.invalid (Moebius)
Groupes : sci.mathDate : 21. Apr 2024, 17:32:29
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <v03f2s$cuh2$1@dont-email.me>
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Am 20.04.2024 um 20:40 schrieb WM:
Le 20/04/2024 à 19:17, Richard Damon a écrit :
On 4/20/24 12:42 PM, WM wrote:
It must be possible to double all elements.
>
Of course you can double all the elements, they just double into a subset of themselves.
>
Impossible.
Ach, red doch ned so einen Quark daher, Mensch.
{2*n : n e IN} c IN.
Alle geraden (natürlichen) Zahlen sind natürliche Zahlen. Erzählst Du Deinen Studenten an der THA etwas anderes?
Proof: Let k in {2*n : n e IN}. Then there is an n in IN such that k = 2*n. Since IN is closed unter multiplication and 2 is in IN too, 2*n in IN and hence k in IN. Hence {2*n : n e IN} c IN. qed
See:
https://www.cuemath.com/questions/which-of-the-following-sets-are-closed-under-multiplication-select-all-that-apply/