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Alle geraden (natürlichen) Zahlen sind natürliche Zahlen. Erzählst Du Deinen Studenten an der THA etwas anderes?No, you are right. But not all doubling results in even natural numbers.
Proof: Let k in {2*n : n e IN}. Then there is an n in IN such that k = 2*n. Since IN is closed unter multiplication and 2 is in IN too, 2*n in IN and hence k in IN. Hence {2*n : n e IN} c IN. qedProof: The original set ℕ fits into (0, ω). The doubled set doesn't.
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