Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how

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Sujet : Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how
De : wolfgang.mueckenheim (at) *nospam* tha.de (WM)
Groupes : sci.math
Date : 22. Apr 2024, 18:56:31
Autres entêtes
Organisation : Nemoweb
Message-ID : <TOi3R27_R7Mf-S1lta4Gw1zD8r8@jntp>
References : 1 2 3 4 5 6 7 8 9 10
User-Agent : Nemo/0.999a
Le 22/04/2024 à 19:32, Jim Burns a écrit :
On 4/22/2024 11:35 AM, WM wrote:

0, 1, 2, 3, ...,   w  = X
|  |  |  |  |||    |
0, 2, 4, 6, ..., w*2  = Y
>
The original set fits in (0, ω).
The doubled set doesn't.
 ⦅0,ω+ω⦆ fits ⦅0,ω⦆
No. ω+ω = ω*2.
Regards, WM

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