Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how

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Sujet : Re: because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how
De : wolfgang.mueckenheim (at) *nospam* tha.de (WM)
Groupes : sci.math
Date : 06. May 2024, 20:00:27
Autres entêtes
Organisation : Nemoweb
Message-ID : <b-z0VNf3CGKWOIYDMjJSeWgSP4k@jntp>
References : 1 2 3 4 5 6 7 8 9 10
User-Agent : Nemo/0.999a
Le 06/05/2024 à 02:10, Moebius a écrit :
Am 03.05.2024 um 22:31 schrieb WM:
Le 03/05/2024 à 21:32, Jim Burns a écrit :
 
Each number which CAN be counted.to from 0 is before
ℵ₀.many numbers which CAN be counted.to from 0
 If all could be counted to, they would not remain after every [number which can be] counted [to].
 Du bringst hier wieder einmal die Quantoren durcheinander.
Nein.
∀n ∈ ℕ_def: |ℕ \ {1, 2, 3, ..., n}| = ℵo
|ℕ \ {1, 2, 3, ...}| = 0 Regards, WM

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