Re: how

Le 15/05/2024 à 19:30, Jim Burns a écrit :

On 5/15/2024 9:30 AM, WM wrote:

Le 14/05/2024 à 22:07, Jim Burns a écrit :

 

NUF(x) changes from 0 to ℵ₀ in (-x′/2,x′/2)
but x′ ∉ (-x′/2,x′/2)

>
For every definable x'.

 For each x' ∈ ℝ⁺ such that,

Let me know the coordinate x where the first ℵ₀ unit fractions sit.

 No point x exists such that NUF(x) = 1

Then there exists a point where ℵ₀ unit fractions sit? Tell me where.

You (WM) say
∀x > 0: NUF(x) = ℵ₀
is incorrect.

That is obvious.

 Which is to say, you (WM) say
∃x > 0: NUF(x) < ℵ₀
is correct.

If you disagree tell me where the first point loaded with ℵ₀ unit fractions is.

 | Assume
| ∃x > 0: NUF(x) < ℵ₀
| is correct.
|
| Assume
| x′ exists such that |⅟ℕ∩(0,x′]| < ℵ₀
|
| ⅟ℕ∩(0,x′] is totally.ordered and finite.

Not in the dark numbers.

∀x > 0: NUF(x) = ℵ₀
is correct.

Tell me where the first point loaded with ℵ₀ unit fractions is.
Regads, WM