Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how

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Sujet : Re: universal quantification, because g⤨(g⁻¹(x)) = g(y) [1/2] Re: how
De : james.g.burns (at) *nospam* att.net (Jim Burns)
Groupes : sci.math
Date : 19. May 2024, 18:28:12
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <2ef1f2f6-ac86-4995-816f-32834e48c571@att.net>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
User-Agent : Mozilla Thunderbird
On 5/18/2024 4:11 PM, Ross Finlayson wrote:
On 05/18/2024 11:16 AM, Jim Burns wrote:
On 5/18/2024 12:09 PM, Ross Finlayson wrote:

One can contrive simple inductive arguments
that _nothing_ is so.
>
An example of such an argument
would be clarifying here.

Says nothing,
says nothing,
says nothing,
says nothing,
....
>
See,
just saying so doesn't make it so,
something that _goes_ has a _place_ to go.
Explain to me how that is an inductive argument.
----
Here is an inductive argument for n⁺¹≠n
BASE CASE.
⎛ Background for finite ordinals
⎝ k⁺¹≠0
for k=0
0⁺¹≠0
STEP CASE.
⎛ Background for finite ordinals
⎝ j≠k  ⇒  j⁺¹≠k⁺¹
for  j=n⁺¹  k=n
n⁺¹≠n  ⇒  n⁺¹⁺¹≠n⁺¹
Therefore,
for each finite ordinal n,  n⁺¹≠n
by induction.
----
In the context of finite ordinals,
that is complete, in that
we know by that argument that,
for each finite ordinal n,  n⁺¹≠n
There exists a fuller argument which
details _how_ we know that,
the part which we don't often see,
because that part is essentially unchanged
from invocation to invocation of "induction"
Here is the fuller inductive argument for n⁺¹≠n
| Assume a finite.ordinal counter.example nₓ
| nₓ⁺¹=nₓ
|
| ⎛ Background for ordinals
| ⎜ The set of counter.examples
| ⎝ holds a first or is empty.
|
| There is a counter.example nₓ
| There is a first counter.example n₁
| n₁⁺¹=n₁
| k < n₁  ⇒  k⁺¹≠k
|
| ⎛ Background for finite.ordinals
| ⎜ Finite.ordinal n is 0  or
| ⎜  it can be decremented  and
| ⎝  each before.ordinal can be decremented or is 0
|
| finite.ordinal nₓ
| n₁ < nₓ
| n₁=0  or  n₁ can be decremented.
|
| 1.
| n₁=0
| 0⁺¹=0
| BASE CASE: 0⁺¹≠0
| Contradiction.
|
| 2.
| n₁ can be decremented.
| n₁⁻¹ < n₁
| (n₁⁻¹)⁺¹ ≠ n₁⁻¹
| STEP CASE:  n⁺¹≠n  ⇒  n⁺¹⁺¹≠n⁺¹
| n₁⁺¹≠n₁
| However,
| n₁⁺¹=n₁
| Contradiction.
|
| Contradiction or contradiction.
Therefore,
a finite.ordinal counter.example nₓ not.exists
For each finite.ordinal n:  n⁺¹≠n
Completely.
----
Suppose we want a proof of some property P(n)
for the complete domain of finite.ordinals
We can swap out
proofs of  0⁺¹≠0  and of  n⁺¹≠n ⇒ n⁺¹⁺¹≠n⁺¹
and swap in
proofs of  P(0)  and of  P(n) ⇒ P(n⁺¹)
and we will have a correct proof with
a necessarily correct conclusion.
A proof.by.induction is a _general_ form
into which details can be inserted which
make it a correct proof of a _particular_ claim
not unlike a proof.by.contradiction,
in that respect.
What we often _call_ a proof.by.induction is
the details to be swapped into the fuller proof.
It's the _whole_ proof, seen and unseen,
which makes the conclusion invincibly complete.

See,
just saying so doesn't make it so,
something that _goes_ has a _place_ to go.
Yes,
just saying so doesn't _make_ it so.
Even
saying so within
a finite sequence of only not.first.false claims
doesn't _make_ it so.
However,
that allows us to _know_ that it's so.
Proof.by.induction is a telescope, not a ray gun.

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