Re: how

Le 13/06/2024 à 20:53, "Chris M. Thomasson" a écrit :

On 6/13/2024 3:48 AM, WM wrote:

Fact is: If we assume the existence of ω at the ordinal line, then something must exist before, either dark numbers or nothing. There is no third alternative. Or can you imagine one?

 Let be imagine something that was dark:
 A = 1024^42426969

Then A^A^A is no longer dark, let alone

 B = A + 1
 A and B were already in the set of natural numbers, right?

Of course.
Regards, WM