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Le 13/06/2024 à 20:53, "Chris M. Thomasson" a écrit :So, the following sequence is never dark?On 6/13/2024 3:48 AM, WM wrote:Then A^A^A is no longer dark, let aloneFact is: If we assume the existence of ω at the ordinal line, then something must exist before, either dark numbers or nothing. There is no third alternative. Or can you imagine one?>
Let be imagine something that was dark:
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A = 1024^42426969
Okay.B = A + 1Of course.
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A and B were already in the set of natural numbers, right?
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