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Le 26/06/2024 à 12:40, FromTheRafters a écrit :See Cardinal Arithmetic again, paying close attention to the transfinite.WM has brought this to us :>>Of course not, a set contains *all* of its elements.>Corollary-question: Does the number of nines grow when in 0.999 the decimal point is shifted by one or more position?What do you think multiplying by ten does to a continued decimal expansion representation?
You must understand that no natural number can be added to the complete set.
And all are indices of the nines in 0.999... .>Therefore no index can be added here. 9.999... has as many nines as 0.999... .9.999... is not a set.
But the indices indexing the nines in 0.999... are the set ℕ. After shifting the decimal point, there are just these indices at the right of the decimal point. But one of them does not index a nine.>After the decimal point, there is a difference. In completed infinity.You are
using logic. The set of indices remains unchanges, the row of nines do not acquire another one.
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