Sujet : Re: Does the number of nines increase?
De : noreply (at) *nospam* example.com (joes)
Groupes : sci.mathDate : 28. Jun 2024, 18:23:43
Autres entêtes
Organisation : i2pn2 (i2pn.org)
Message-ID : <v5mriv$1d3t3$7@i2pn2.org>
References : 1 2 3 4 5 6 7 8 9
User-Agent : Pan/0.145 (Duplicitous mercenary valetism; d7e168a git.gnome.org/pan2)
Am Fri, 28 Jun 2024 13:55:34 +0000 schrieb WM:
Le 28/06/2024 à 10:38, joes a écrit :
Am Thu, 27 Jun 2024 12:15:30 +0000 schrieb WM:
Le 26/06/2024 à 23:55, Jim Burns a écrit :
WM thinks an infinite number is
very.large.but.finite
No, I assume that sets are complete. Therefore ℕ_0 as a proper
superset of ℕ has one elements more than ℕ. Infinity does not make
them equal.
Infinity does not have a predecessor like finite numbers.
What does „complete” mean?
It means that no natural number can be added to {0, 1, 2, 3, ..., ω}
Duh, the set of all natural numbers N contains all of them.
It means that the subtraction of the complete set leaves {0, 1, 2, 3,
..., ω} \ ℕ = {0, ω}.
It means that in {0, 1, 2, 3, ..., ω} before ω there is a natural
number.
There is not, since there are infinitely many of them.
With which numbers do you describe the sizes of N and N_0?
Most of them are dark and cannot be used as individuals.
Not their elements. I was asking for their number, how many
of them there are.
…