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Le 29/06/2024 à 11:37, FromTheRafters a écrit :a = 1/9 = .(1) = (.111...)Ross Finlayson pretended :All nines are from the sequence 0.9, 0.09, 0.009, ... None of the ℵo nines makes its partial sum 0,9, 0.99, 0.999, ... equal to 1. ℵo nines fail.You know, or it "goes" to.>
Yes, but the number of nines in the sequence after the radix point is countably infinite rather than finite, hence NaN in this context.
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