Sujet : Re: Does the number of nines increase?
De : james.g.burns (at) *nospam* att.net (Jim Burns)
Groupes : sci.mathDate : 01. Jul 2024, 19:32:45
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <081c69e8-6170-4a42-b586-927cac810712@att.net>
References : 1 2 3 4 5 6 7 8 9
User-Agent : Mozilla Thunderbird
On 7/1/2024 12:13 PM, WM wrote:
Le 30/06/2024 à 22:59, Jim Burns a écrit :
On 6/27/2024 8:15 AM, WM wrote:
I assume that sets are complete.
>
I (JB) think that what you (WM) call 'logic' is that
each nonempty set has a trichotomous order such that
each nonempty subset holds a first and a last,
whether its first or last is visibleᵂᴹ or darkᵂᴹ
>
Is that what you're saying?
>
Yes, but
only under the pr4condition of completed infinity.
Completed.infinityᵂᴹ is finiteⁿᵒᵗᐧᵂᴹ.
https://en.wikipedia.org/wiki/Finite_set| Necessary and sufficient conditions for finiteness
| (Paul Stäckel)
| S can be given a total ordering which is
| well-ordered both forwards and backwards.
| That is, every non-empty subset of S has
| both a least and a greatest element in the subset.
The set ℕ of all finiteⁿᵒᵗᐧᵂᴹ cardinals
cannot be given
a total ordering which is
well-ordered both forwards and backwards.
ℕ isn't a finiteⁿᵒᵗᐧᵂᴹ set.
For each finiteⁿᵒᵗᐧᵂᴹ cardinal j ∈ ℕ
j ends an initial segment {0,1,2,...,j} of ℕ
which can be given a total ordering which is
well-ordered both forwards and backwards.
{0,1,2,...,j} is a finiteⁿᵒᵗᐧᵂᴹ set.
For each finiteⁿᵒᵗᐧᵂᴹ cardinal j ∈ ℕ
j begins an end segment {j,j+1,...} of ℕ
which cannot be given a total ordering which is
well-ordered both forwards and backwards.
{j,j+1,...} isn't a finiteⁿᵒᵗᐧᵂᴹ set.